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  • Graphing y =:
  • 1/(x^2+5x-6)
  • x^3-6x^2-15x-8
  • (x-3)²
  • (x+2)/(x-3)
  • Identical expressions

  • one /(x* nine)-x/(two *x)
  • 1 divide by (x multiply by 9) minus x divide by (2 multiply by x)
  • one divide by (x multiply by nine) minus x divide by (two multiply by x)
  • 1/(x9)-x/(2x)
  • 1/x9-x/2x
  • 1 divide by (x*9)-x divide by (2*x)
  • Similar expressions

  • 1/(x*9)+x/(2*x)

Graphing y = 1/(x*9)-x/(2*x)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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        1     x 
f(x) = --- - ---
       x*9   2*x
$$f{\left(x \right)} = - \frac{x}{2 x} + \frac{1}{9 x}$$
f = -x/(2*x) + 1/(9*x)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 0$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$- \frac{x}{2 x} + \frac{1}{9 x} = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = \frac{2}{9}$$
Numerical solution
$$x_{1} = 0.222222222222222$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to 1/(x*9) - x/(2*x).
$$\frac{1}{0 \cdot 9} - \frac{0}{0 \cdot 2}$$
The result:
$$f{\left(0 \right)} = \text{NaN}$$
- the solutions of the equation d'not exist
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{\frac{1}{9} \frac{1}{x}}{x} - \frac{1}{2 x} + \frac{1}{2 x} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2}{9 x^{3}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = 0$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(- \frac{x}{2 x} + \frac{1}{9 x}\right) = - \frac{1}{2}$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = - \frac{1}{2}$$
$$\lim_{x \to \infty}\left(- \frac{x}{2 x} + \frac{1}{9 x}\right) = - \frac{1}{2}$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = - \frac{1}{2}$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of 1/(x*9) - x/(2*x), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{- \frac{x}{2 x} + \frac{1}{9 x}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{- \frac{x}{2 x} + \frac{1}{9 x}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$- \frac{x}{2 x} + \frac{1}{9 x} = - \frac{1}{2} - \frac{1}{9 x}$$
- No
$$- \frac{x}{2 x} + \frac{1}{9 x} = \frac{1}{2} + \frac{1}{9 x}$$
- No
so, the function
not is
neither even, nor odd