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  • Graphing y =:
  • x^3-2x^2+x
  • x^2+5x+4
  • x^2-4x+6
  • -x^2-x
  • Identical expressions

  • one /coth(x)
  • 1 divide by hyperbolic co tangent of gent of (x)
  • one divide by hyperbolic co tangent of gent of (x)
  • 1/cothx
  • 1 divide by coth(x)

Graphing y = 1/coth(x)

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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          1   
f(x) = -------
       coth(x)
$$f{\left(x \right)} = \frac{1}{\coth{\left(x \right)}}$$
f = 1/coth(x)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{1}{\coth{\left(x \right)}} = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to 1/coth(x).
$$\frac{1}{\coth{\left(0 \right)}}$$
The result:
$$f{\left(0 \right)} = 0$$
The point:
(0, 0)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{1}{\sinh^{2}{\left(x \right)} \coth^{2}{\left(x \right)}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \left(- \cosh{\left(x \right)} + \frac{1}{\sinh{\left(x \right)} \coth{\left(x \right)}}\right)}{\sinh^{3}{\left(x \right)} \coth^{2}{\left(x \right)}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \frac{1}{\coth{\left(x \right)}} = -1$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = -1$$
$$\lim_{x \to \infty} \frac{1}{\coth{\left(x \right)}} = 1$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 1$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of 1/coth(x), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{1}{x \coth{\left(x \right)}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{1}{x \coth{\left(x \right)}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{1}{\coth{\left(x \right)}} = - \frac{1}{\coth{\left(x \right)}}$$
- No
$$\frac{1}{\coth{\left(x \right)}} = \frac{1}{\coth{\left(x \right)}}$$
- Yes
so, the function
is
odd