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Graphing y = |x^2+8x+12|

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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f(x) = |x  + 8*x + 12|
f(x)=(x2+8x)+12f{\left(x \right)} = \left|{\left(x^{2} + 8 x\right) + 12}\right|
f = |x^2 + 8*x + 12|
The graph of the function
02468-8-6-4-2-10100200
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
(x2+8x)+12=0\left|{\left(x^{2} + 8 x\right) + 12}\right| = 0
Solve this equation
The points of intersection with the axis X:

Analytical solution
x1=6x_{1} = -6
x2=2x_{2} = -2
Numerical solution
x1=2x_{1} = -2
x2=6x_{2} = -6
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to |x^2 + 8*x + 12|.
(02+08)+12\left|{\left(0^{2} + 0 \cdot 8\right) + 12}\right|
The result:
f(0)=12f{\left(0 \right)} = 12
The point:
(0, 12)
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
d2dx2f(x)=0\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
d2dx2f(x)=\frac{d^{2}}{d x^{2}} f{\left(x \right)} =
the second derivative
2(4(x+4)2δ(x2+8x+12)+sign(x2+8x+12))=02 \left(4 \left(x + 4\right)^{2} \delta\left(x^{2} + 8 x + 12\right) + \operatorname{sign}{\left(x^{2} + 8 x + 12 \right)}\right) = 0
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
limx(x2+8x)+12=\lim_{x \to -\infty} \left|{\left(x^{2} + 8 x\right) + 12}\right| = \infty
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
limx(x2+8x)+12=\lim_{x \to \infty} \left|{\left(x^{2} + 8 x\right) + 12}\right| = \infty
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of |x^2 + 8*x + 12|, divided by x at x->+oo and x ->-oo
limx((x2+8x)+12x)=\lim_{x \to -\infty}\left(\frac{\left|{\left(x^{2} + 8 x\right) + 12}\right|}{x}\right) = -\infty
Let's take the limit
so,
inclined asymptote on the left doesn’t exist
limx((x2+8x)+12x)=\lim_{x \to \infty}\left(\frac{\left|{\left(x^{2} + 8 x\right) + 12}\right|}{x}\right) = \infty
Let's take the limit
so,
inclined asymptote on the right doesn’t exist
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
(x2+8x)+12=x28x+12\left|{\left(x^{2} + 8 x\right) + 12}\right| = \left|{x^{2} - 8 x + 12}\right|
- No
(x2+8x)+12=x28x+12\left|{\left(x^{2} + 8 x\right) + 12}\right| = - \left|{x^{2} - 8 x + 12}\right|
- No
so, the function
not is
neither even, nor odd