Mister Exam

Other calculators

Graphing y = -x^3-x-2

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
          3        
f(x) = - x  - x - 2
$$f{\left(x \right)} = \left(- x^{3} - x\right) - 2$$
f = -x^3 - x - 2
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\left(- x^{3} - x\right) - 2 = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = -1$$
Numerical solution
$$x_{1} = -1$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to -x^3 - x - 2.
$$-2 + \left(- 0^{3} - 0\right)$$
The result:
$$f{\left(0 \right)} = -2$$
The point:
(0, -2)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- 3 x^{2} - 1 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- 6 x = 0$$
Solve this equation
The roots of this equation
$$x_{1} = 0$$

Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left(-\infty, 0\right]$$
Convex at the intervals
$$\left[0, \infty\right)$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\left(- x^{3} - x\right) - 2\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\left(- x^{3} - x\right) - 2\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of -x^3 - x - 2, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\left(- x^{3} - x\right) - 2}{x}\right) = -\infty$$
Let's take the limit
so,
inclined asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\frac{\left(- x^{3} - x\right) - 2}{x}\right) = -\infty$$
Let's take the limit
so,
inclined asymptote on the right doesn’t exist
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\left(- x^{3} - x\right) - 2 = x^{3} + x - 2$$
- No
$$\left(- x^{3} - x\right) - 2 = - x^{3} - x + 2$$
- No
so, the function
not is
neither even, nor odd