Mister Exam

Graphing y = -sqrt(x-3)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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f(x) = -\/ x - 3 
$$f{\left(x \right)} = - \sqrt{x - 3}$$
f = -sqrt(x - 3)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$- \sqrt{x - 3} = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = 3$$
Numerical solution
$$x_{1} = 3$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to -sqrt(x - 3).
$$- \sqrt{-3}$$
The result:
$$f{\left(0 \right)} = - \sqrt{3} i$$
The point:
(0, -i*sqrt(3))
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{1}{2 \sqrt{x - 3}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{1}{4 \left(x - 3\right)^{\frac{3}{2}}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(- \sqrt{x - 3}\right) = - \infty i$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(- \sqrt{x - 3}\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of -sqrt(x - 3), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(- \frac{\sqrt{x - 3}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(- \frac{\sqrt{x - 3}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$- \sqrt{x - 3} = - \sqrt{- x - 3}$$
- No
$$- \sqrt{x - 3} = \sqrt{- x - 3}$$
- No
so, the function
not is
neither even, nor odd