Mister Exam
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-
How to use it?
- Graphing y =:
- (x^2-x-6)/(x-2)
- -x^2(x+4)^2
- x^3+3x^2-9x+15
- -x^2+6x-8
-
Identical expressions
- - one / three x^3-4x
- minus 1 divide by 3x cubed minus 4x
- minus one divide by three x cubed minus 4x
- -1/3x3-4x
- -1/3x³-4x
- -1/3x to the power of 3-4x
- -1 divide by 3x^3-4x
-
Similar expressions
- 1/3x^3-4x
- -1/3x^3+4x
Graphing y = -1/3x^3-4x
The solution
You have entered
[src]
3
x
f(x) = - -- - 4*x
3
$$f{\left(x \right)} = - \frac{x^{3}}{3} - 4 x$$
f = -x^3/3 - 4*x
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$- \frac{x^{3}}{3} - 4 x = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
so we need to solve the equation:
$$- \frac{x^{3}}{3} - 4 x = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- x^{2} - 4 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- x^{2} - 4 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- 2 x = 0$$
Solve this equation
The roots of this equation
$$x_{1} = 0$$
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left(-\infty, 0\right]$$
Convex at the intervals
$$\left[0, \infty\right)$$
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- 2 x = 0$$
Solve this equation
The roots of this equation
$$x_{1} = 0$$
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left(-\infty, 0\right]$$
Convex at the intervals
$$\left[0, \infty\right)$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(- \frac{x^{3}}{3} - 4 x\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(- \frac{x^{3}}{3} - 4 x\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
$$\lim_{x \to -\infty}\left(- \frac{x^{3}}{3} - 4 x\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(- \frac{x^{3}}{3} - 4 x\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of -x^3/3 - 4*x, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{- \frac{x^{3}}{3} - 4 x}{x}\right) = -\infty$$
Let's take the limit
so,
inclined asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\frac{- \frac{x^{3}}{3} - 4 x}{x}\right) = -\infty$$
Let's take the limit
so,
inclined asymptote on the right doesn’t exist
$$\lim_{x \to -\infty}\left(\frac{- \frac{x^{3}}{3} - 4 x}{x}\right) = -\infty$$
Let's take the limit
so,
inclined asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\frac{- \frac{x^{3}}{3} - 4 x}{x}\right) = -\infty$$
Let's take the limit
so,
inclined asymptote on the right doesn’t exist
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$- \frac{x^{3}}{3} - 4 x = \frac{x^{3}}{3} + 4 x$$
- No
$$- \frac{x^{3}}{3} - 4 x = - \frac{x^{3}}{3} - 4 x$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$- \frac{x^{3}}{3} - 4 x = \frac{x^{3}}{3} + 4 x$$
- No
$$- \frac{x^{3}}{3} - 4 x = - \frac{x^{3}}{3} - 4 x$$
- No
so, the function
not is
neither even, nor odd
The graph