Mister Exam
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-
How to use it?
- Graphing y =:
- x^2+3x-10
-
(x^2+3)/(x-1)
- x^2-10x+27
- ((x+1)^2)/(x-2)
-
Identical expressions
- -ln one +x/1-x
- minus ln1 plus x divide by 1 minus x
- minus ln one plus x divide by 1 minus x
- -ln1+x divide by 1-x
-
Similar expressions
- -ln1-x/1-x
- -ln(1+x)/(1-x)
- ln1+x/1-x
- -ln((1+x)/(1-x))
- -ln1+x/1+x
Graphing y = -ln1+x/1-x
The solution
You have entered
[src]
x
f(x) = -log(1) + - - x
1
$$f{\left(x \right)} = - x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)$$
f = -x + x/1 - log(1)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right) = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
so we need to solve the equation:
$$- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right) = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
$$\lim_{x \to -\infty}\left(- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of -log(1) + x/1 - x, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right)}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right) = - \log{\left(1 \right)}$$
- No
$$- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right) = \log{\left(1 \right)}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right) = - \log{\left(1 \right)}$$
- No
$$- x + \left(\frac{x}{1} - \log{\left(1 \right)}\right) = \log{\left(1 \right)}$$
- No
so, the function
not is
neither even, nor odd