Mister Exam

Other calculators

  • How to use it?

  • Graphing y =:
  • x⁴-1
  • |x+4|-1
  • -x^4+1
  • (x^3+x)/(x^2-1)
  • Identical expressions

  • - five / four *x+(seven / two)
  • minus 5 divide by 4 multiply by x plus (7 divide by 2)
  • minus five divide by four multiply by x plus (seven divide by two)
  • -5/4x+(7/2)
  • -5/4x+7/2
  • -5 divide by 4*x+(7 divide by 2)
  • Similar expressions

  • 5/4*x+(7/2)
  • -5/4*x-(7/2)

Graphing y = -5/4*x+(7/2)

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
         5*x   7
f(x) = - --- + -
          4    2
$$f{\left(x \right)} = \frac{7}{2} - \frac{5 x}{4}$$
f = 7/2 - 5*x/4
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{7}{2} - \frac{5 x}{4} = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = \frac{14}{5}$$
Numerical solution
$$x_{1} = 2.8$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to -5*x/4 + 7/2.
$$\frac{7}{2} - 0$$
The result:
$$f{\left(0 \right)} = \frac{7}{2}$$
The point:
(0, 7/2)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{5}{4} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{7}{2} - \frac{5 x}{4}\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\frac{7}{2} - \frac{5 x}{4}\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of -5*x/4 + 7/2, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\frac{7}{2} - \frac{5 x}{4}}{x}\right) = - \frac{5}{4}$$
Let's take the limit
so,
inclined asymptote equation on the left:
$$y = - \frac{5 x}{4}$$
$$\lim_{x \to \infty}\left(\frac{\frac{7}{2} - \frac{5 x}{4}}{x}\right) = - \frac{5}{4}$$
Let's take the limit
so,
inclined asymptote equation on the right:
$$y = - \frac{5 x}{4}$$
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{7}{2} - \frac{5 x}{4} = \frac{5 x}{4} + \frac{7}{2}$$
- No
$$\frac{7}{2} - \frac{5 x}{4} = - \frac{5 x}{4} - \frac{7}{2}$$
- No
so, the function
not is
neither even, nor odd