Mister Exam
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-
How to use it?
- Graphing y =:
- -x^3+3x^2-2
- x^3-12*x+2
-
|x|x+3|x|-5x
- x^-5
-
Identical expressions
- -arctg(x+ one)
- minus arctg(x plus 1)
- minus arctg(x plus one)
- -arctgx+1
-
Similar expressions
- -arctg(x-1)
- arctg(x+1)
Graphing y = -arctg(x+1)
The solution
You have entered
[src]
f(x) = -atan(x + 1)
$$f{\left(x \right)} = - \operatorname{atan}{\left(x + 1 \right)}$$
f = -atan(x + 1)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$- \operatorname{atan}{\left(x + 1 \right)} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = -1$$
Numerical solution
$$x_{1} = -1$$
so we need to solve the equation:
$$- \operatorname{atan}{\left(x + 1 \right)} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = -1$$
Numerical solution
$$x_{1} = -1$$
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{1}{\left(x + 1\right)^{2} + 1} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{1}{\left(x + 1\right)^{2} + 1} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \left(x + 1\right)}{\left(\left(x + 1\right)^{2} + 1\right)^{2}} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = -1$$
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left[-1, \infty\right)$$
Convex at the intervals
$$\left(-\infty, -1\right]$$
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \left(x + 1\right)}{\left(\left(x + 1\right)^{2} + 1\right)^{2}} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = -1$$
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left[-1, \infty\right)$$
Convex at the intervals
$$\left(-\infty, -1\right]$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(- \operatorname{atan}{\left(x + 1 \right)}\right) = \frac{\pi}{2}$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = \frac{\pi}{2}$$
$$\lim_{x \to \infty}\left(- \operatorname{atan}{\left(x + 1 \right)}\right) = - \frac{\pi}{2}$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = - \frac{\pi}{2}$$
$$\lim_{x \to -\infty}\left(- \operatorname{atan}{\left(x + 1 \right)}\right) = \frac{\pi}{2}$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = \frac{\pi}{2}$$
$$\lim_{x \to \infty}\left(- \operatorname{atan}{\left(x + 1 \right)}\right) = - \frac{\pi}{2}$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = - \frac{\pi}{2}$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of -atan(x + 1), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(- \frac{\operatorname{atan}{\left(x + 1 \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(- \frac{\operatorname{atan}{\left(x + 1 \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(- \frac{\operatorname{atan}{\left(x + 1 \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(- \frac{\operatorname{atan}{\left(x + 1 \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$- \operatorname{atan}{\left(x + 1 \right)} = \operatorname{atan}{\left(x - 1 \right)}$$
- No
$$- \operatorname{atan}{\left(x + 1 \right)} = - \operatorname{atan}{\left(x - 1 \right)}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$- \operatorname{atan}{\left(x + 1 \right)} = \operatorname{atan}{\left(x - 1 \right)}$$
- No
$$- \operatorname{atan}{\left(x + 1 \right)} = - \operatorname{atan}{\left(x - 1 \right)}$$
- No
so, the function
not is
neither even, nor odd