Inclined asymptote can be found by calculating the limit of log(3)*x + 1, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{x \log{\left(3 \right)} + 1}{x}\right) = \log{\left(3 \right)}$$
Let's take the limitso,
inclined asymptote equation on the left:
$$y = x \log{\left(3 \right)}$$
$$\lim_{x \to \infty}\left(\frac{x \log{\left(3 \right)} + 1}{x}\right) = \log{\left(3 \right)}$$
Let's take the limitso,
inclined asymptote equation on the right:
$$y = x \log{\left(3 \right)}$$