Let's find the inflection points, we'll need to solve the equation for this
dx2d2f(x)=0(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
dx2d2f(x)=the second derivative4x3+ex24x−4x3+ex(12x2+ex)2+ex=0Solve this equationThe roots of this equation
x1=77.198731330601x2=77.0124850969537x3=60.6525896883197x4=77.0838695174728x5=100x6=64.5261565642568x7=6.04601858923138x8=78x9=70.3757428307212x10=94.25x11=74.3855050604014x12=72.3229314979781x13=51.1071218018637x14=80x15=98x16=52.9946996224697x17=62.5865072888081x18=77.1862034519915x19=96x20=77.8203482568241x21=77.2141744553657x22=56.8055953511733x23=77.3618108426466x24=45.5503908345065x25=54.8948687600961x26=84x27=77.0258369002429x28=82x29=40.2805348535545x30=90x31=47.3809756966331x32=43.7493508424981x33=66.4707529956174x34=77.0566778668501x35=68.419631664462x36=77.1427592390923x37=77.1877987770559x38=86x39=88x40=58.7252674784738x41=77.6251821417523x42=92x43=0x44=41.9873266562552x45=49.234743592684Сonvexity and concavity intervals:Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
[90,∞)Convex at the intervals
(−∞,0]