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  • Graphing y =:
  • x^4/4-x^3/3-x^2
  • x^3-3x-7
  • x^3-3x-2
  • x^3+3x-2
  • Identical expressions

  • log1/ five (x2– three)
  • logarithm of 1 divide by 5(x2–3)
  • logarithm of 1 divide by five (x2– three)
  • log1/5x2–3
  • log1 divide by 5(x2–3)

Graphing y = log1/5(x2–3)

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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        log(1)         
f(x2) = ------*(x2 - 3)
          5            
$$f{\left(x_{2} \right)} = \frac{\log{\left(1 \right)}}{5} \left(x_{2} - 3\right)$$
f(x2) = (log(1)/5)*(x2 - 3)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X2 at f(x2) = 0
so we need to solve the equation:
$$\frac{\log{\left(1 \right)}}{5} \left(x_{2} - 3\right) = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X2
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x2 equals 0:
substitute x2 = 0 to (log(1)/5)*(x2 - 3).
$$\left(-3\right) \frac{\log{\left(1 \right)}}{5}$$
The result:
$$f{\left(0 \right)} = 0$$
The point:
(0, 0)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x_{2}} f{\left(x_{2} \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x_{2}} f{\left(x_{2} \right)} = $$
the first derivative
$$\frac{\log{\left(1 \right)}}{5} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x_{2}^{2}} f{\left(x_{2} \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x_{2}^{2}} f{\left(x_{2} \right)} = $$
the second derivative
$$0 = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x2->+oo and x2->-oo
$$\lim_{x_{2} \to -\infty}\left(\frac{\log{\left(1 \right)}}{5} \left(x_{2} - 3\right)\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x_{2} \to \infty}\left(\frac{\log{\left(1 \right)}}{5} \left(x_{2} - 3\right)\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of (log(1)/5)*(x2 - 3), divided by x2 at x2->+oo and x2 ->-oo
$$\lim_{x_{2} \to -\infty}\left(\frac{\left(x_{2} - 3\right) \log{\left(1 \right)}}{5 x_{2}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x_{2} \to \infty}\left(\frac{\left(x_{2} - 3\right) \log{\left(1 \right)}}{5 x_{2}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f(x2) = f(-x2) и f(x2) = -f(-x2).
So, check:
$$\frac{\log{\left(1 \right)}}{5} \left(x_{2} - 3\right) = \frac{\left(- x_{2} - 3\right) \log{\left(1 \right)}}{5}$$
- No
$$\frac{\log{\left(1 \right)}}{5} \left(x_{2} - 3\right) = - \frac{\left(- x_{2} - 3\right) \log{\left(1 \right)}}{5}$$
- No
so, the function
not is
neither even, nor odd