Mister Exam
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-
How to use it?
- Graphing y =:
-
x^3-4x
- x^2(x-2)^2
- (x^2-x+1)/(x-1)
-
x^2-6x+5
-
Identical expressions
- tanh(x/ one -)
- hyperbolic tangent of gent of (x divide by 1 minus )
- hyperbolic tangent of gent of (x divide by one minus )
- tanhx/1-
- tanh(x divide by 1-)
-
Similar expressions
- tanh(x/1+)
Graphing y = tanh(x/1-)
The solution
You have entered
[src]
/x\
f(x) = tanh|-|
\1/
$$f{\left(x \right)} = \tanh{\left(\frac{x}{1} \right)}$$
f = tanh(x/1)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\tanh{\left(\frac{x}{1} \right)} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
so we need to solve the equation:
$$\tanh{\left(\frac{x}{1} \right)} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$1 - \tanh^{2}{\left(\frac{x}{1} \right)} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$1 - \tanh^{2}{\left(\frac{x}{1} \right)} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$2 \left(\tanh^{2}{\left(x \right)} - 1\right) \tanh{\left(x \right)} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = 0$$
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left(-\infty, 0\right]$$
Convex at the intervals
$$\left[0, \infty\right)$$
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$2 \left(\tanh^{2}{\left(x \right)} - 1\right) \tanh{\left(x \right)} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = 0$$
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left(-\infty, 0\right]$$
Convex at the intervals
$$\left[0, \infty\right)$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \tanh{\left(\frac{x}{1} \right)} = -1$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = -1$$
$$\lim_{x \to \infty} \tanh{\left(\frac{x}{1} \right)} = 1$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 1$$
$$\lim_{x \to -\infty} \tanh{\left(\frac{x}{1} \right)} = -1$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = -1$$
$$\lim_{x \to \infty} \tanh{\left(\frac{x}{1} \right)} = 1$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 1$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of tanh(x/1), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\tanh{\left(\frac{x}{1} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\tanh{\left(\frac{x}{1} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{\tanh{\left(\frac{x}{1} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\tanh{\left(\frac{x}{1} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\tanh{\left(\frac{x}{1} \right)} = - \tanh{\left(x \right)}$$
- No
$$\tanh{\left(\frac{x}{1} \right)} = \tanh{\left(x \right)}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$\tanh{\left(\frac{x}{1} \right)} = - \tanh{\left(x \right)}$$
- No
$$\tanh{\left(\frac{x}{1} \right)} = \tanh{\left(x \right)}$$
- No
so, the function
not is
neither even, nor odd