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Graphing y = 14*cos(x)-15*x+1

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The graph:

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Intersection points:

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Piecewise:

The solution

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f(x) = 14*cos(x) - 15*x + 1
$$f{\left(x \right)} = \left(- 15 x + 14 \cos{\left(x \right)}\right) + 1$$
f = -15*x + 14*cos(x) + 1
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\left(- 15 x + 14 \cos{\left(x \right)}\right) + 1 = 0$$
Solve this equation
The points of intersection with the axis X:

Numerical solution
$$x_{1} = 0.749741018042687$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to 14*cos(x) - 15*x + 1.
$$1 + \left(- 0 + 14 \cos{\left(0 \right)}\right)$$
The result:
$$f{\left(0 \right)} = 15$$
The point:
(0, 15)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- 14 \sin{\left(x \right)} - 15 = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$- 14 \cos{\left(x \right)} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = \frac{\pi}{2}$$
$$x_{2} = \frac{3 \pi}{2}$$

Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left[\frac{\pi}{2}, \frac{3 \pi}{2}\right]$$
Convex at the intervals
$$\left(-\infty, \frac{\pi}{2}\right] \cup \left[\frac{3 \pi}{2}, \infty\right)$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\left(- 15 x + 14 \cos{\left(x \right)}\right) + 1\right) = \infty$$
Let's take the limit
so,
horizontal asymptote on the left doesn’t exist
$$\lim_{x \to \infty}\left(\left(- 15 x + 14 \cos{\left(x \right)}\right) + 1\right) = -\infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of 14*cos(x) - 15*x + 1, divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\left(- 15 x + 14 \cos{\left(x \right)}\right) + 1}{x}\right) = -15$$
Let's take the limit
so,
inclined asymptote equation on the left:
$$y = - 15 x$$
$$\lim_{x \to \infty}\left(\frac{\left(- 15 x + 14 \cos{\left(x \right)}\right) + 1}{x}\right) = -15$$
Let's take the limit
so,
inclined asymptote equation on the right:
$$y = - 15 x$$
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\left(- 15 x + 14 \cos{\left(x \right)}\right) + 1 = 15 x + 14 \cos{\left(x \right)} + 1$$
- No
$$\left(- 15 x + 14 \cos{\left(x \right)}\right) + 1 = - 15 x - 14 \cos{\left(x \right)} - 1$$
- No
so, the function
not is
neither even, nor odd