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5^-1/(x-1)^2
  • How to use it?

  • Graphing y =:
  • x(2-x)^2
  • x√2-x
  • -x²+6x-5
  • x^2-8x
  • Identical expressions

  • five ^- one /(x- one)^ two
  • 5 to the power of minus 1 divide by (x minus 1) squared
  • five to the power of minus one divide by (x minus one) to the power of two
  • 5-1/(x-1)2
  • 5-1/x-12
  • 5^-1/(x-1)²
  • 5 to the power of -1/(x-1) to the power of 2
  • 5^-1/x-1^2
  • 5^-1 divide by (x-1)^2
  • Similar expressions

  • 5^-1/(x+1)^2
  • 5^+1/(x-1)^2

Graphing y = 5^-1/(x-1)^2

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
           1     
f(x) = ----------
                2
       5*(x - 1) 
$$f{\left(x \right)} = \frac{1}{5 \left(x - 1\right)^{2}}$$
f = 1/(5*((x - 1*1)^2))
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 1$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{1}{5 \left(x - 1\right)^{2}} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to 1/(5*((x - 1*1)^2)).
$$\frac{1}{5 \left(\left(-1\right) 1 + 0\right)^{2}}$$
The result:
$$f{\left(0 \right)} = \frac{1}{5}$$
The point:
(0, 1/5)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{- 2 x + 2}{5 \left(x - 1\right)^{4}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{6}{5 \left(x - 1\right)^{4}} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Vertical asymptotes
Have:
$$x_{1} = 1$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{1}{5 \left(x - 1\right)^{2}}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(\frac{1}{5 \left(x - 1\right)^{2}}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of 1/(5*((x - 1*1)^2)), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{1}{5 x \left(x - 1\right)^{2}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{1}{5 x \left(x - 1\right)^{2}}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{1}{5 \left(x - 1\right)^{2}} = \frac{1}{5 \left(- x - 1\right)^{2}}$$
- No
$$\frac{1}{5 \left(x - 1\right)^{2}} = - \frac{1}{5 \left(- x - 1\right)^{2}}$$
- No
so, the function
not is
neither even, nor odd
The graph
Graphing y = 5^-1/(x-1)^2