Mister Exam
Other calculators
-
How to use it?
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- -19*x-15*y=15
- 16*x+14*y=-14
- Equation:
-
Equation x^3=3
-
Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
-
Equation x^2+6=5x
- Sum of series:
-
-1
- Derivative of:
-
-1
- Integral of d{x}:
-
-1
-
Identical expressions
- - three *x+ four *y=- one
- minus 3 multiply by x plus 4 multiply by y equally minus 1
- minus three multiply by x plus four multiply by y equally minus one
- -3x+4y=-1
-
Similar expressions
- 3*x+4*y=-1
- -3*x-4*y=-1
- -3*x+4*y=+1
Express x in terms of y where -3*x+4*y=-1
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 3 x = - 4 y - 1$$
Divide both parts of the equation by -3
We get the answer: x = 1/3 + 4*y/3
-3*x+4*y = -1
Looking for similar summands in the left part:
-3*x + 4*y = -1
Move the summands with the other variables
from left part to right part, we given:
$$- 3 x = - 4 y - 1$$
Divide both parts of the equation by -3
x = -1 - 4*y / (-3)
We get the answer: x = 1/3 + 4*y/3
Rapid solution
[src]
1 4*re(y) 4*I*im(y)
x1 = - + ------- + ---------
3 3 3
$$x_{1} = \frac{4 \operatorname{re}{\left(y\right)}}{3} + \frac{4 i \operatorname{im}{\left(y\right)}}{3} + \frac{1}{3}$$
x1 = 4*re(y)/3 + 4*i*im(y)/3 + 1/3