Mister Exam
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How to use it?
- Express {x} in terms of y where:
- -16*x-19*y=-4
- -9*x+17*y=-3
- -3*x+4*y=-1
- -10*x-15*y=-11
- Equation:
-
Equation cos(x)-1=0
-
Equation (x+3)^4-4(x+3)^2-5=0
-
Equation x^2+14*x+24=0
-
Equation 0*x=10
- Derivative of:
- -4
- Integral of d{x}:
-
-4
- Limit of the function:
- -4
-
Identical expressions
- - sixteen *x- nineteen *y=- four
- minus 16 multiply by x minus 19 multiply by y equally minus 4
- minus sixteen multiply by x minus nineteen multiply by y equally minus four
- -16x-19y=-4
-
Similar expressions
- 16*x-19*y=-4
- -16*x-19*y=+4
- -16*x+19*y=-4
Express x in terms of y where -16*x-19*y=-4
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = 19 y - 4$$
Divide both parts of the equation by -16
We get the answer: x = 1/4 - 19*y/16
-16*x-19*y = -4
Looking for similar summands in the left part:
-19*y - 16*x = -4
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = 19 y - 4$$
Divide both parts of the equation by -16
x = -4 + 19*y / (-16)
We get the answer: x = 1/4 - 19*y/16
Rapid solution
[src]
1 19*re(y) 19*I*im(y)
x1 = - - -------- - ----------
4 16 16
$$x_{1} = - \frac{19 \operatorname{re}{\left(y\right)}}{16} - \frac{19 i \operatorname{im}{\left(y\right)}}{16} + \frac{1}{4}$$
x1 = -19*re(y)/16 - 19*i*im(y)/16 + 1/4