Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- 8*x-9*y=-1
- -6*x+11*y=-5
- -3*x-19*y=-9
- 9*x+19*y=2
- Equation:
-
Equation x^3=3
-
Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
- Equation 3^8-x=27
- Sum of series:
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10
- Derivative of:
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10
- Integral of d{x}:
-
10
-
Identical expressions
- - fifteen *x+ one *y= ten
- minus 15 multiply by x plus 1 multiply by y equally 10
- minus fifteen multiply by x plus one multiply by y equally ten
- -15x+1y=10
-
Similar expressions
- 15*x+1*y=10
- -15*x-1*y=10
Express x in terms of y where -15*x+1*y=10
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 15 x = 10 - y$$
Divide both parts of the equation by -15
We get the answer: x = -2/3 + y/15
-15*x+1*y = 10
Looking for similar summands in the left part:
y - 15*x = 10
Move the summands with the other variables
from left part to right part, we given:
$$- 15 x = 10 - y$$
Divide both parts of the equation by -15
x = 10 - y / (-15)
We get the answer: x = -2/3 + y/15
Rapid solution
[src]
2 re(y) I*im(y)
x1 = - - + ----- + -------
3 15 15
$$x_{1} = \frac{\operatorname{re}{\left(y\right)}}{15} + \frac{i \operatorname{im}{\left(y\right)}}{15} - \frac{2}{3}$$
x1 = re(y)/15 + i*im(y)/15 - 2/3