Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- -19*x-15*y=15
- 16*x+14*y=-14
- Equation:
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Equation x^3=3
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Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
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Equation x^2+6=5x
- Derivative of:
- -15
- Sum of series:
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-15
- Limit of the function:
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-15
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Identical expressions
- five *x+ thirteen *y=- fifteen
- 5 multiply by x plus 13 multiply by y equally minus 15
- five multiply by x plus thirteen multiply by y equally minus fifteen
- 5x+13y=-15
-
Similar expressions
- 5*x+13*y=+15
- 5*x-13*y=-15
Express x in terms of y where 5*x+13*y=-15
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$5 x = - 13 y - 15$$
Divide both parts of the equation by 5
We get the answer: x = -3 - 13*y/5
5*x+13*y = -15
Looking for similar summands in the left part:
5*x + 13*y = -15
Move the summands with the other variables
from left part to right part, we given:
$$5 x = - 13 y - 15$$
Divide both parts of the equation by 5
x = -15 - 13*y / (5)
We get the answer: x = -3 - 13*y/5
Rapid solution
[src]
13*re(y) 13*I*im(y)
x1 = -3 - -------- - ----------
5 5
$$x_{1} = - \frac{13 \operatorname{re}{\left(y\right)}}{5} - \frac{13 i \operatorname{im}{\left(y\right)}}{5} - 3$$
x1 = -13*re(y)/5 - 13*i*im(y)/5 - 3