Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x+5)(2x-4)+24=0
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Equation 3(x-2)(x+4)=2x^2+x
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Equation 0,8(x-2)+2,6=0,5(7+x)
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Equation (2log3*2log3)*(8sinx−√3)−7log3*(8sinx−√3)+6=0
- Express {x} in terms of y where:
- 8*x-7*y=-13
- 15*x-15*y=16
- 9*x+18*y=6
- (x^2+y^2-1)^3+x^2*y^3=0
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Identical expressions
- zero , eight (x- two)+ two , six = zero , five (seven +x)
- 0,8(x minus 2) plus 2,6 equally 0,5(7 plus x)
- zero , eight (x minus two) plus two , six equally zero , five (seven plus x)
- 0,8x-2+2,6=0,57+x
- 0,8(x-2)+2,6=O,5(7+x)
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Similar expressions
- 0,8(x-2)-2,6=0,5(7+x)
- 0,8(x+2)+2,6=0,5(7+x)
- 0,8(x-2)+2,6=0,5(7-x)
0,8(x-2)+2,6=0,5(7+x) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
4*(x - 2) 13 7 + x
--------- + -- = -----
5 5 2
$$\frac{4 \left(x - 2\right)}{5} + \frac{13}{5} = \frac{x + 7}{2}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$\frac{4 x}{5} = \frac{x}{2} + \frac{5}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{3 x}{10} = \frac{5}{2}$$
Divide both parts of the equation by 3/10
We get the answer: x = 25/3
(4/5)*(x-2)+(13/5) = (1/2)*(7+x)
Expand brackets in the left part
4/5x-2+13/5 = (1/2)*(7+x)
Expand brackets in the right part
4/5x-2+13/5 = 1/27+x
Looking for similar summands in the left part:
1 + 4*x/5 = 1/27+x
Move free summands (without x)
from left part to right part, we given:
$$\frac{4 x}{5} = \frac{x}{2} + \frac{5}{2}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{3 x}{10} = \frac{5}{2}$$
Divide both parts of the equation by 3/10
x = 5/2 / (3/10)
We get the answer: x = 25/3
Sum and product of roots
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sum
25/3
$$\frac{25}{3}$$
=
25/3
$$\frac{25}{3}$$
product
25/3
$$\frac{25}{3}$$
=
25/3
$$\frac{25}{3}$$
25/3
The graph