Mister Exam
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How to use it?
- Equation:
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Equation laplace(x)=(39/40)
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Equation 0,4x+3,8=2,6-0,8x
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Equation (7-x)^2=(x+3)^2
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Equation 8x=4
- Express {x} in terms of y where:
- 12*x+2*y=-9
- 2*x+6*y=-2
- -9*x-16*y=-1
- -18*x-11*y=7
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Identical expressions
- zero ,4x+ three , eight = two , six - zero ,8x
- 0,4x plus 3,8 equally 2,6 minus 0,8x
- zero ,4x plus three , eight equally two , six minus zero ,8x
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Similar expressions
- 0,4x-3,8=2,6-0,8x
- 0,4x+3,8=2,6+0,8x
0,4x+3,8=2,6-0,8x equation
The teacher will be very surprised to see your correct solution 😉
The solution
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2*x 19 13 4*x --- + -- = -- - --- 5 5 5 5
$$\frac{2 x}{5} + \frac{19}{5} = \frac{13}{5} - \frac{4 x}{5}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{2 x}{5} = - \frac{4 x}{5} - \frac{6}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{6 x}{5} = - \frac{6}{5}$$
Divide both parts of the equation by 6/5
We get the answer: x = -1
(2/5)*x+(19/5) = (13/5)-(4/5)*x
Expand brackets in the left part
2/5x+19/5 = (13/5)-(4/5)*x
Expand brackets in the right part
2/5x+19/5 = 13/5-4/5x
Move free summands (without x)
from left part to right part, we given:
$$\frac{2 x}{5} = - \frac{4 x}{5} - \frac{6}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{6 x}{5} = - \frac{6}{5}$$
Divide both parts of the equation by 6/5
x = -6/5 / (6/5)
We get the answer: x = -1
The graph