(7-x)^2=(x+3)^2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
(7-x)^2 = (x+3)^2
Expand expressions:
49 + x^2 - 14*x = (x+3)^2
(7-x)^2 = 9 + x^2 + 6*x
Reducing, you get:
40 - 20*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 20 x = -40$$
Divide both parts of the equation by -20
x = -40 / (-20)
We get the answer: x = 2
Sum and product of roots
[src]
$$2$$
$$2$$
$$2$$
$$2$$