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z^2+z+1=0

z^2+z+1=0 equation

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Numerical solution:

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The solution

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 2            
z  + z + 1 = 0
$$\left(z^{2} + z\right) + 1 = 0$$
Detail solution
This equation is of the form
a*z^2 + b*z + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$z_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$z_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 1$$
$$c = 1$$
, then
D = b^2 - 4 * a * c = 

(1)^2 - 4 * (1) * (1) = -3

Because D<0, then the equation
has no real roots,
but complex roots is exists.
z1 = (-b + sqrt(D)) / (2*a)

z2 = (-b - sqrt(D)) / (2*a)

or
$$z_{1} = - \frac{1}{2} + \frac{\sqrt{3} i}{2}$$
$$z_{2} = - \frac{1}{2} - \frac{\sqrt{3} i}{2}$$
Vieta's Theorem
it is reduced quadratic equation
$$p z + q + z^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 1$$
$$q = \frac{c}{a}$$
$$q = 1$$
Vieta Formulas
$$z_{1} + z_{2} = - p$$
$$z_{1} z_{2} = q$$
$$z_{1} + z_{2} = -1$$
$$z_{1} z_{2} = 1$$
The graph
Rapid solution [src]
               ___
       1   I*\/ 3 
z1 = - - - -------
       2      2   
$$z_{1} = - \frac{1}{2} - \frac{\sqrt{3} i}{2}$$
               ___
       1   I*\/ 3 
z2 = - - + -------
       2      2   
$$z_{2} = - \frac{1}{2} + \frac{\sqrt{3} i}{2}$$
z2 = -1/2 + sqrt(3)*i/2
Sum and product of roots [src]
sum
          ___             ___
  1   I*\/ 3      1   I*\/ 3 
- - - ------- + - - + -------
  2      2        2      2   
$$\left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right) + \left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right)$$
=
-1
$$-1$$
product
/          ___\ /          ___\
|  1   I*\/ 3 | |  1   I*\/ 3 |
|- - - -------|*|- - + -------|
\  2      2   / \  2      2   /
$$\left(- \frac{1}{2} - \frac{\sqrt{3} i}{2}\right) \left(- \frac{1}{2} + \frac{\sqrt{3} i}{2}\right)$$
=
1
$$1$$
1
Numerical answer [src]
z1 = -0.5 - 0.866025403784439*i
z2 = -0.5 + 0.866025403784439*i
z2 = -0.5 + 0.866025403784439*i
The graph
z^2+z+1=0 equation