Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -14*x+4*y=-16
- -13*x-10*y=5
- 9*x-1*y=17
- 7*x+6*y=20
- Equation:
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Equation x^2+4*x+4=0
- Equation x^2+81=0
-
Equation 6*3+x=72
-
Equation x^3+x^2=0
- Sum of series:
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13
- Canonical form:
- 13
- Derivative of:
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13
-
Identical expressions
- - twelve *x- eight *y= thirteen
- minus 12 multiply by x minus 8 multiply by y equally 13
- minus twelve multiply by x minus eight multiply by y equally thirteen
- -12x-8y=13
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Similar expressions
- 12*x-8*y=13
- -12*x+8*y=13
Express x in terms of y where -12*x-8*y=13
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 12 x = 8 y + 13$$
Divide both parts of the equation by -12
We get the answer: x = -13/12 - 2*y/3
-12*x-8*y = 13
Looking for similar summands in the left part:
-12*x - 8*y = 13
Move the summands with the other variables
from left part to right part, we given:
$$- 12 x = 8 y + 13$$
Divide both parts of the equation by -12
x = 13 + 8*y / (-12)
We get the answer: x = -13/12 - 2*y/3
Rapid solution
[src]
13 2*re(y) 2*I*im(y)
x1 = - -- - ------- - ---------
12 3 3
$$x_{1} = - \frac{2 \operatorname{re}{\left(y\right)}}{3} - \frac{2 i \operatorname{im}{\left(y\right)}}{3} - \frac{13}{12}$$
x1 = -2*re(y)/3 - 2*i*im(y)/3 - 13/12