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x^2+10*x-96=0 equation

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Numerical solution:

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The solution

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x  + 10*x - 96 = 0
$$\left(x^{2} + 10 x\right) - 96 = 0$$
Detail solution
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 10$$
$$c = -96$$
, then
D = b^2 - 4 * a * c = 

(10)^2 - 4 * (1) * (-96) = 484

Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = 6$$
$$x_{2} = -16$$
Vieta's Theorem
it is reduced quadratic equation
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 10$$
$$q = \frac{c}{a}$$
$$q = -96$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = -10$$
$$x_{1} x_{2} = -96$$
Rapid solution [src]
x1 = -16
$$x_{1} = -16$$
x2 = 6
$$x_{2} = 6$$
x2 = 6
Sum and product of roots [src]
sum
-16 + 6
$$-16 + 6$$
=
-10
$$-10$$
product
-16*6
$$- 96$$
=
-96
$$-96$$
-96
Numerical answer [src]
x1 = 6.0
x2 = -16.0
x2 = -16.0