Mister Exam
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- Equation:
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Equation 2+3x=-2x-13
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Equation x^2-8x+15=0
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Equation x^2=-2
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Equation 9/(x-2)=9/2
- Express {x} in terms of y where:
- 4*x+16*y=6
- -6*x+1*y=14
- -8*x-12*y=15
- 9*x+8*y=6
- Sum of series:
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9/2
- Limit of the function:
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9/2
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Identical expressions
- nine /(x- two)= nine / two
- 9 divide by (x minus 2) equally 9 divide by 2
- nine divide by (x minus two) equally nine divide by two
- 9/x-2=9/2
- 9 divide by (x-2)=9 divide by 2
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Similar expressions
- (x-9)/((3*x))=(x-9)/2
- 36/4-x^2+2=1-x/x+2-9/x-2
- 9/(x+2)=9/2
- 9/(x-25)=25/(x-9)
- (-60-(90^(2)*22.806^(2))/(24*23*10^(-6)*8509.09^(2))+(8509.09)/(23*10^(-6)*61.8*10^(9)*117*10^(-6)))+(90^(2)*3.235^(2))/(24*23*10^(-6)*x^(2))-(x)/(23*10^(-6)*61.8*10^(9)*117*10^(-6))=-53
- 6/5=(x-29)/(x-21)
- 13,4=((6,7*10^-11)*x*5*10^9)/25
9/(x-2)=9/2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{9}{x - 2} = \frac{9}{2}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$9 \cdot \frac{2}{9} = 1 \left(x - 2\right)$$
$$2 = x - 2$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x - 4$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = -4$$
Divide both parts of the equation by -1
We get the answer: x = 4
$$\frac{9}{x - 2} = \frac{9}{2}$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 9
b1 = -2 + x
a2 = 1
b2 = 2/9
so we get the equation
$$9 \cdot \frac{2}{9} = 1 \left(x - 2\right)$$
$$2 = x - 2$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x - 4$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = -4$$
Divide both parts of the equation by -1
x = -4 / (-1)
We get the answer: x = 4
The graph