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x^2+4x-5=0

x^2+4x-5=0 equation

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Numerical solution:

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The solution

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x  + 4*x - 5 = 0
(x2+4x)5=0\left(x^{2} + 4 x\right) - 5 = 0
Detail solution
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
x1=Db2ax_{1} = \frac{\sqrt{D} - b}{2 a}
x2=Db2ax_{2} = \frac{- \sqrt{D} - b}{2 a}
where D = b^2 - 4*a*c - it is the discriminant.
Because
a=1a = 1
b=4b = 4
c=5c = -5
, then
D = b^2 - 4 * a * c = 

(4)^2 - 4 * (1) * (-5) = 36

Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
x1=1x_{1} = 1
x2=5x_{2} = -5
Vieta's Theorem
it is reduced quadratic equation
px+q+x2=0p x + q + x^{2} = 0
where
p=bap = \frac{b}{a}
p=4p = 4
q=caq = \frac{c}{a}
q=5q = -5
Vieta Formulas
x1+x2=px_{1} + x_{2} = - p
x1x2=qx_{1} x_{2} = q
x1+x2=4x_{1} + x_{2} = -4
x1x2=5x_{1} x_{2} = -5
The graph
05-20-15-10-51015-200200
Sum and product of roots [src]
sum
-5 + 1
5+1-5 + 1
=
-4
4-4
product
-5
5-5
=
-5
5-5
-5
Rapid solution [src]
x1 = -5
x1=5x_{1} = -5
x2 = 1
x2=1x_{2} = 1
x2 = 1
Numerical answer [src]
x1 = 1.0
x2 = -5.0
x2 = -5.0
The graph
x^2+4x-5=0 equation