Mister Exam
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How to use it?
- Equation:
- Equation 8cos^2(x)+6sin(x)-3=0
- Equation x^(2)-12+(36/X^(2))+2((x/2)-(3/x))=0
-
Equation 20-7(5x-4)=6
- Equation (49^sinx)^cosx=7^(sqrt3)^sinx
- Express {x} in terms of y where:
- -1*x-19*y=-10
- 5*x+5*y=20
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- sqrt(x^2+y^2+4x-6y-12)+(x^2+10x-27)=8-|y-9|+|y-3|
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Identical expressions
- x^(two)- twelve +(thirty-six /X^(two))+ two ((x/ two)-(three /x))= zero
- x to the power of (2) minus 12 plus (36 divide by X to the power of (2)) plus 2((x divide by 2) minus (3 divide by x)) equally 0
- x to the power of (two) minus twelve plus (thirty minus six divide by X to the power of (two)) plus two ((x divide by two) minus (three divide by x)) equally zero
- x(2)-12+(36/X(2))+2((x/2)-(3/x))=0
- x2-12+36/X2+2x/2-3/x=0
- x^2-12+36/X^2+2x/2-3/x=0
- x^(2)-12+(36/X^(2))+2((x/2)-(3/x))=O
- x^(2)-12+(36 divide by X^(2))+2((x divide by 2)-(3 divide by x))=0
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Similar expressions
- x^(2)-12+(36/X^(2))-2((x/2)-(3/x))=0
- x^(2)+12+(36/X^(2))+2((x/2)-(3/x))=0
- x^(2)-12-(36/X^(2))+2((x/2)-(3/x))=0
- x^(2)-12+(36/X^(2))+2((x/2)+(3/x))=0
x^(2)-12+(36/X^(2))+2((x/2)-(3/x))=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
2 36 /x 3\
x - 12 + -- + 2*|- - -| = 0
2 \2 x/
x
$$2 \left(\frac{x}{2} - \frac{3}{x}\right) + \left(\left(x^{2} - 12\right) + \frac{36}{x^{2}}\right) = 0$$
Rapid solution
[src]
x1 = -3
$$x_{1} = -3$$
x2 = 2
$$x_{2} = 2$$
___ x3 = -\/ 6
$$x_{3} = - \sqrt{6}$$
___ x4 = \/ 6
$$x_{4} = \sqrt{6}$$
x4 = sqrt(6)
Sum and product of roots
[src]
sum
___ ___ -3 + 2 - \/ 6 + \/ 6
$$\left(- \sqrt{6} + \left(-3 + 2\right)\right) + \sqrt{6}$$
=
-1
$$-1$$
product
/ ___\ ___ -3*2*\-\/ 6 /*\/ 6
$$\sqrt{6} \cdot - 6 \left(- \sqrt{6}\right)$$
=
36
$$36$$
36