Mister Exam
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How to use it?
- Equation:
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Equation x/(x^2-1)=0
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Equation 2x-3(x-3)=12
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Equation x^2/(x+6)=1/2
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Equation 4x+2(1-3x)=13
- Express {x} in terms of y where:
- 15*x-5*y=-5
- 18*x+20*y=-2
- -5*x-6*y=-1
- -17*x-15*y=-17
- Derivative of:
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x^2-9
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(x+3)^2
- Graphing y =:
- x^2-9
- (x+3)^2
- Integral of d{x}:
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x^2-9
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(x+3)^2
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Identical expressions
- x^ two - nine =(x+ three)^ two
- x squared minus 9 equally (x plus 3) squared
- x to the power of two minus nine equally (x plus three) to the power of two
- x2-9=(x+3)2
- x2-9=x+32
- x²-9=(x+3)²
- x to the power of 2-9=(x+3) to the power of 2
- x^2-9=x+3^2
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Similar expressions
- x^2-9=(x-3)^2
- x^2+9=(x+3)^2
- (x+3)^2=(x+11)^2
- (-x^2-9)/(x^2-9)^2=0
- x^2-9*x+14=0
x^2-9=(x+3)^2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$- 6 x = 18$$
Divide both parts of the equation by -6
We get the answer: x = -3
x^2-9 = (x+3)^2
Expand expressions:
x^2-9 = 9 + x^2 + 6*x
Reducing, you get:
-18 - 6*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 6 x = 18$$
Divide both parts of the equation by -6
x = 18 / (-6)
We get the answer: x = -3
The graph