(x+3)^2=(x+11)^2 equation
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The solution
Detail solution
Given the equation:
(x+3)^2 = (x+11)^2
Expand expressions:
9 + x^2 + 6*x = (x+11)^2
(x+3)^2 = 121 + x^2 + 22*x
Reducing, you get:
-112 - 16*x = 0
Move free summands (without x)
from left part to right part, we given:
$$- 16 x = 112$$
Divide both parts of the equation by -16
x = 112 / (-16)
We get the answer: x = -7
Sum and product of roots
[src]
$$-7 + 0$$
$$-7$$
$$1 \left(-7\right)$$
$$-7$$