Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3x=2
-
Equation x^2+7x=18
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Equation x^2-4x=0
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Equation (y^4+4*y^2-12)/4=0
- Express {x} in terms of y where:
- 13*x-18*y=-17
- -7*x-19*y=-18
- 5*x+12*y=18
- -12*x-8*y=13
- Graphing y =:
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x^2-4x
- Integral of d{x}:
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x^2-4x
- Canonical form:
- x^2-4x
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Identical expressions
- x^ two -4x= zero
- x squared minus 4x equally 0
- x to the power of two minus 4x equally zero
- x2-4x=0
- x²-4x=0
- x to the power of 2-4x=0
- x^2-4x=O
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Similar expressions
- sqrt(x^2-4x+4)-1=sqrt((3x-5)*(3-x))
- x^2+4x=0
- x^2-4*x+8+2-3*x=0
- (9-2x)/(x^2-4x)=(3)/(x-4)+(6)/(x)
x^2-4x=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -4$$
$$c = 0$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 4$$
$$x_{2} = 0$$
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -4$$
$$c = 0$$
, then
D = b^2 - 4 * a * c =
(-4)^2 - 4 * (1) * (0) = 16
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 4$$
$$x_{2} = 0$$
Vieta's Theorem
it is reduced quadratic equation
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = -4$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 4$$
$$x_{1} x_{2} = 0$$
$$p x + q + x^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = -4$$
$$q = \frac{c}{a}$$
$$q = 0$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 4$$
$$x_{1} x_{2} = 0$$
The graph