Mister Exam

Other calculators


x^2-4*x+8+2-3*x=0

x^2-4*x+8+2-3*x=0 equation

The teacher will be very surprised to see your correct solution 😉

v

Numerical solution:

Do search numerical solution at [, ]

The solution

You have entered [src]
 2                        
x  - 4*x + 8 + 2 - 3*x = 0
$$x^{2} - 4 x - 3 x + 2 + 8 = 0$$
Detail solution
This equation is of the form
$$a\ x^2 + b\ x + c = 0$$
A quadratic equation can be solved using the discriminant
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where $D = b^2 - 4 a c$ is the discriminant.
Because
$$a = 1$$
$$b = -7$$
$$c = 10$$
, then
$$D = b^2 - 4\ a\ c = $$
$$\left(-1\right) 1 \cdot 4 \cdot 10 + \left(-7\right)^{2} = 9$$
Because D > 0, then the equation has two roots.
$$x_1 = \frac{(-b + \sqrt{D})}{2 a}$$
$$x_2 = \frac{(-b - \sqrt{D})}{2 a}$$
or
$$x_{1} = 5$$
Simplify
$$x_{2} = 2$$
Simplify
Vieta's Theorem
it is reduced quadratic equation
$$p x + x^{2} + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = -7$$
$$q = \frac{c}{a}$$
$$q = 10$$
Vieta Formulas
$$x_{1} + x_{2} = - p$$
$$x_{1} x_{2} = q$$
$$x_{1} + x_{2} = 7$$
$$x_{1} x_{2} = 10$$
The graph
Rapid solution [src]
x_1 = 2
$$x_{1} = 2$$
x_2 = 5
$$x_{2} = 5$$
Sum and product of roots [src]
sum
2 + 5
$$\left(2\right) + \left(5\right)$$
=
7
$$7$$
product
2 * 5
$$\left(2\right) * \left(5\right)$$
=
10
$$10$$
Numerical answer [src]
x1 = 5.0
x2 = 2.0
x2 = 2.0
The graph
x^2-4*x+8+2-3*x=0 equation