Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation -x^2+5*x-6=0
- Equation x-y=7
-
Equation 2^x=32
-
Equation (x+3)^4+2*(x+3)^2-8=0
- Express {x} in terms of y where:
- 19*x-12*y=16
- -11*x-3*y=14
- -2*x+14*y=9
- 6*x+9*y=-9
- Graphing y =:
- x^3-8
- Factor polynomial:
- x^3-8
- Integral of d{x}:
- x^3-8
-
Identical expressions
- x^ three - eight = zero
- x cubed minus 8 equally 0
- x to the power of three minus eight equally zero
- x3-8=0
- x³-8=0
- x to the power of 3-8=0
- x^3-8=O
-
Similar expressions
- x^3+8=0
x^3-8=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$x^{3} - 8 = 0$$
Because equation degree is equal to = 3 - does not contain even numbers in the numerator, then
the equation has single real root.
Get the root 3-th degree of the equation sides:
We get:
$$\sqrt[3]{x^{3}} = \sqrt[3]{8}$$
or
$$x = 2$$
We get the answer: x = 2
All other 2 root(s) is the complex numbers.
do replacement:
$$z = x$$
then the equation will be the:
$$z^{3} = 8$$
Any complex number can presented so:
$$z = r e^{i p}$$
substitute to the equation
$$r^{3} e^{3 i p} = 8$$
where
$$r = 2$$
- the magnitude of the complex number
Substitute r:
$$e^{3 i p} = 1$$
Using Euler’s formula, we find roots for p
$$i \sin{\left(3 p \right)} + \cos{\left(3 p \right)} = 1$$
so
$$\cos{\left(3 p \right)} = 1$$
and
$$\sin{\left(3 p \right)} = 0$$
then
$$p = \frac{2 \pi N}{3}$$
where N=0,1,2,3,...
Looping through the values of N and substituting p into the formula for z
Consequently, the solution will be for z:
$$z_{1} = 2$$
$$z_{2} = -1 - \sqrt{3} i$$
$$z_{3} = -1 + \sqrt{3} i$$
do backward replacement
$$z = x$$
$$x = z$$
The final answer:
$$x_{1} = 2$$
$$x_{2} = -1 - \sqrt{3} i$$
$$x_{3} = -1 + \sqrt{3} i$$
$$x^{3} - 8 = 0$$
Because equation degree is equal to = 3 - does not contain even numbers in the numerator, then
the equation has single real root.
Get the root 3-th degree of the equation sides:
We get:
$$\sqrt[3]{x^{3}} = \sqrt[3]{8}$$
or
$$x = 2$$
We get the answer: x = 2
All other 2 root(s) is the complex numbers.
do replacement:
$$z = x$$
then the equation will be the:
$$z^{3} = 8$$
Any complex number can presented so:
$$z = r e^{i p}$$
substitute to the equation
$$r^{3} e^{3 i p} = 8$$
where
$$r = 2$$
- the magnitude of the complex number
Substitute r:
$$e^{3 i p} = 1$$
Using Euler’s formula, we find roots for p
$$i \sin{\left(3 p \right)} + \cos{\left(3 p \right)} = 1$$
so
$$\cos{\left(3 p \right)} = 1$$
and
$$\sin{\left(3 p \right)} = 0$$
then
$$p = \frac{2 \pi N}{3}$$
where N=0,1,2,3,...
Looping through the values of N and substituting p into the formula for z
Consequently, the solution will be for z:
$$z_{1} = 2$$
$$z_{2} = -1 - \sqrt{3} i$$
$$z_{3} = -1 + \sqrt{3} i$$
do backward replacement
$$z = x$$
$$x = z$$
The final answer:
$$x_{1} = 2$$
$$x_{2} = -1 - \sqrt{3} i$$
$$x_{3} = -1 + \sqrt{3} i$$
Vieta's Theorem
it is reduced cubic equation
$$p x^{2} + q x + v + x^{3} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
$$v = \frac{d}{a}$$
$$v = -8$$
Vieta Formulas
$$x_{1} + x_{2} + x_{3} = - p$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = q$$
$$x_{1} x_{2} x_{3} = v$$
$$x_{1} + x_{2} + x_{3} = 0$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = 0$$
$$x_{1} x_{2} x_{3} = -8$$
$$p x^{2} + q x + v + x^{3} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 0$$
$$v = \frac{d}{a}$$
$$v = -8$$
Vieta Formulas
$$x_{1} + x_{2} + x_{3} = - p$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = q$$
$$x_{1} x_{2} x_{3} = v$$
$$x_{1} + x_{2} + x_{3} = 0$$
$$x_{1} x_{2} + x_{1} x_{3} + x_{2} x_{3} = 0$$
$$x_{1} x_{2} x_{3} = -8$$
Sum and product of roots
[src]
sum
___ ___ 2 + -1 - I*\/ 3 + -1 + I*\/ 3
$$\left(2 + \left(-1 - \sqrt{3} i\right)\right) + \left(-1 + \sqrt{3} i\right)$$
=
0
$$0$$
product
/ ___\ / ___\ 2*\-1 - I*\/ 3 /*\-1 + I*\/ 3 /
$$2 \left(-1 - \sqrt{3} i\right) \left(-1 + \sqrt{3} i\right)$$
=
8
$$8$$
8
Rapid solution
[src]
x1 = 2
$$x_{1} = 2$$
___ x2 = -1 - I*\/ 3
$$x_{2} = -1 - \sqrt{3} i$$
___ x3 = -1 + I*\/ 3
$$x_{3} = -1 + \sqrt{3} i$$
x3 = -1 + sqrt(3)*i
Numerical answer
[src]
x1 = 2.0
x2 = -1.0 - 1.73205080756888*i
x3 = -1.0 + 1.73205080756888*i
x3 = -1.0 + 1.73205080756888*i
The graph