Given the equation: x4+2x2−3=0 Do replacement v=x2 then the equation will be the: v2+2v−3=0 This equation is of the form a∗v2+b∗v+c=0 A quadratic equation can be solved using the discriminant The roots of the quadratic equation: v1=2aD−b v2=2a−D−b where D=b2−4ac is the discriminant. Because a=1 b=2 c=−3 , then D=b2−4∗a∗c= 22−1⋅4(−3)=16 Because D > 0, then the equation has two roots. v1=2a(−b+D) v2=2a(−b−D) or v1=1 Simplify v2=−3 Simplify The final answer: Because v=x2 then x1=v1 x2=−v1 x3=v2 x4=−v2 then: x1=10+11⋅121=1 x2=1(−1)121+10=−1 x3=10+11(−3)21=3i x4=10+1(−1)(−3)21=−3i