log8(5x-1)=2 equation
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The solution
Detail solution
Given the equation
$$\frac{\log{\left(5 x - 1 \right)}}{\log{\left(8 \right)}} = 2$$
$$\frac{\log{\left(5 x - 1 \right)}}{\log{\left(8 \right)}} = 2$$
Let's divide both parts of the equation by the multiplier of log =1/log(8)
$$\log{\left(5 x - 1 \right)} = 2 \log{\left(8 \right)}$$
This equation is of the form:
log(v)=p
By definition log
v=e^p
then
$$5 x - 1 = e^{\frac{2}{\frac{1}{\log{\left(8 \right)}}}}$$
simplify
$$5 x - 1 = 64$$
$$5 x = 65$$
$$x = 13$$
Sum and product of roots
[src]
$$13$$
$$13$$
$$13$$
$$13$$