Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2+4*x+4=0
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Equation (x^2-4)^2+(x^2-3x-10)^2=0
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Equation -x/3+x+7=3
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Equation -20*(x-13)=-220
- Express {x} in terms of y where:
- -14*x+4*y=-16
- -13*x-10*y=5
- 9*x-1*y=17
- -12*x-8*y=13
- x+y-3
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Identical expressions
- x+y- three = zero
- x plus y minus 3 equally 0
- x plus y minus three equally zero
- x+y-3=O
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Similar expressions
- x2*(2*x+y)-3*y2*(x+5)=4
- -3*(2*x+y)-3*(y-2*x)=0
- x-y-3=0
- x^2*(2*x+y)-3*y^2*(x+5)=4
- x+y+3=0
x+y-3=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$x + y = 3$$
Move the summands with the other variables
from left part to right part, we given:
$$x = 3 - y$$
We get the answer: x = 3 - y
x+y-3 = 0
Looking for similar summands in the left part:
-3 + x + y = 0
Move free summands (without x)
from left part to right part, we given:
$$x + y = 3$$
Move the summands with the other variables
from left part to right part, we given:
$$x = 3 - y$$
We get the answer: x = 3 - y
The graph
Rapid solution
[src]
x1 = 3 - re(y) - I*im(y)
$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
x1 = -re(y) - i*im(y) + 3
Sum and product of roots
[src]
sum
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
=
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
product
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
=
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
3 - re(y) - i*im(y)