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x+y-3=0 equation

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Numerical solution:

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The solution

You have entered [src]
x + y - 3 = 0
$$\left(x + y\right) - 3 = 0$$
Detail solution
Given the linear equation:
x+y-3 = 0

Looking for similar summands in the left part:
-3 + x + y = 0

Move free summands (without x)
from left part to right part, we given:
$$x + y = 3$$
Move the summands with the other variables
from left part to right part, we given:
$$x = 3 - y$$
We get the answer: x = 3 - y
The graph
Rapid solution [src]
x1 = 3 - re(y) - I*im(y)
$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
x1 = -re(y) - i*im(y) + 3
Sum and product of roots [src]
sum
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
=
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
product
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
=
3 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 3$$
3 - re(y) - i*im(y)