Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^3=4
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Equation x^2+2x+2=0
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Equation 3/(x-5)+8/x=2
- Equation z^3+i=0
- Express {x} in terms of y where:
- -1*x-6*y=18
- 6*x-19*y=-18
- -14*x+18*y=0
- -8*x+3*y=-4
- x+y-1
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Identical expressions
- x+y- one = zero
- x plus y minus 1 equally 0
- x plus y minus one equally zero
- x+y-1=O
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Similar expressions
- x-y-1=0
- x+y+1=0
- -2*sin(x+y)-(1/2)*cos(2*x)+2*sin(y)=0
- sin(x+y)-1,5*x=0,1
- sin(x+y)-1.5*x-0.2=0
x+y-1=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$x + y = 1$$
Move the summands with the other variables
from left part to right part, we given:
$$x = 1 - y$$
We get the answer: x = 1 - y
x+y-1 = 0
Looking for similar summands in the left part:
-1 + x + y = 0
Move free summands (without x)
from left part to right part, we given:
$$x + y = 1$$
Move the summands with the other variables
from left part to right part, we given:
$$x = 1 - y$$
We get the answer: x = 1 - y
The graph
Rapid solution
[src]
x1 = 1 - re(y) - I*im(y)
$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
x1 = -re(y) - i*im(y) + 1
Sum and product of roots
[src]
sum
1 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
=
1 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
product
1 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
=
1 - re(y) - I*im(y)
$$- \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 1$$
1 - re(y) - i*im(y)