Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2+2x+1=-x^2-2x+(-7+2x^2)
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Equation arctan(sin(x))
- Equation (X+3)/5=6+(x/2)
- Equation C^2x-2=21
- Express {x} in terms of y where:
- 9*x+18*y=6
- 15*x-15*y=16
- sqrt(x^2+y^2+4x-6y-12)+(x^2+10x-27)=8-|y-9|+|y-3|
- (x^2+y^2-1)^3+x^2*y^3=0
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Identical expressions
- (X+ three)/ five = six +(x/ two)
- (X plus 3) divide by 5 equally 6 plus (x divide by 2)
- (X plus three) divide by five equally six plus (x divide by two)
- X+3/5=6+x/2
- (X+3) divide by 5=6+(x divide by 2)
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Similar expressions
- (X-3)/5=6+(x/2)
- X+x/2+x/3+x/4+x/5+x/6+x/7+x/8+x/9+x/10+x/11+x/12+x/14+x/14+x/15+x/16+x/17+x/18+x/19+x/20+x/21+x/22+x/23+x/24+x/25+x/26+x/27+x/28+x/29+x/30+x/31+x/32=10682
- 2+x/3-6+x/2=0
- x(2,56+x)/((2,85–x)(1,67–x))=0,152
- (2,36+x)/2=3,639
- (X+3)/5=6-(x/2)
- 2(X+3/5)=x*3,1/5
(X+3)/5=6+(x/2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{5} = \frac{x}{2} + \frac{27}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-3\right) x}{10} = \frac{27}{5}$$
Divide both parts of the equation by -3/10
We get the answer: x = -18
(x+3)/5 = 6+(x/2)
Expand brackets in the left part
x/5+3/5 = 6+(x/2)
Expand brackets in the right part
x/5+3/5 = 6+x/2
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{5} = \frac{x}{2} + \frac{27}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{\left(-3\right) x}{10} = \frac{27}{5}$$
Divide both parts of the equation by -3/10
x = 27/5 / (-3/10)
We get the answer: x = -18