Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2+x=12
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Equation 3x-2(3x-2)=19
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Equation (-2x+1)*(-2x-7)=0
- Equation x-y+1=0
- Express {x} in terms of y where:
- 16*x-17*y=-15
- -4*x-4*y=19
- 15*x+1*y=19
- -5*x-2*y=9
- The double integral of:
- x-y+1
- x-y+1
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Identical expressions
- x-y+ one = zero
- x minus y plus 1 equally 0
- x minus y plus one equally zero
- x-y+1=O
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Similar expressions
- x-y-1=0
- 8*x^2+8*y^2-16*a*(x-y)+15*a^2-48*y-50*a+71=0
- x+y+1=0
x-y+1=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$x - y = -1$$
Move the summands with the other variables
from left part to right part, we given:
$$x = y - 1$$
We get the answer: x = -1 + y
x-y+1 = 0
Looking for similar summands in the left part:
1 + x - y = 0
Move free summands (without x)
from left part to right part, we given:
$$x - y = -1$$
Move the summands with the other variables
from left part to right part, we given:
$$x = y - 1$$
We get the answer: x = -1 + y
The graph
Sum and product of roots
[src]
sum
-1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} - 1$$
=
-1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} - 1$$
product
-1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} - 1$$
=
-1 + I*im(y) + re(y)
$$\operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} - 1$$
-1 + i*im(y) + re(y)
Rapid solution
[src]
x1 = -1 + I*im(y) + re(y)
$$x_{1} = \operatorname{re}{\left(y\right)} + i \operatorname{im}{\left(y\right)} - 1$$
x1 = re(y) + i*im(y) - 1