Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 4(x-1)=2(2x-8)+12
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Equation x^2-18=7*x
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Equation (x-4)/4=(x+3)/7
- Equation 2*x+y=5
- Express {x} in terms of y where:
- 4*x+13*y=8
- 14*x+17*y=19
- 3*x-11*y=20
- -18*x-13*y=2
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Identical expressions
- (x- four)/ four =(x+ three)/ seven
- (x minus 4) divide by 4 equally (x plus 3) divide by 7
- (x minus four) divide by four equally (x plus three) divide by seven
- x-4/4=x+3/7
- (x-4) divide by 4=(x+3) divide by 7
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Similar expressions
- (x*(3*x-4))/(4*sqrt(x^2*(1-x))*(1-x))=0
- (x-4)/4=(x-3)/7
- 1/2x-1-13x-4/4x^2-4x+1=4
- x+3/7=3x-2/2
- x-4/4-2=x/2
- 5*x+(x-3)/4=(4*x-4)/4-8
- (x+4)/4=(x+3)/7
- x+3/7=3x-2/8
(x-4)/4=(x+3)/7 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{4} = \frac{x}{7} + \frac{10}{7}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{3 x}{28} = \frac{10}{7}$$
Divide both parts of the equation by 3/28
We get the answer: x = 40/3
(x-4)/4 = (x+3)/7
Expand brackets in the left part
x/4-4/4 = (x+3)/7
Expand brackets in the right part
x/4-4/4 = x/7+3/7
Move free summands (without x)
from left part to right part, we given:
$$\frac{x}{4} = \frac{x}{7} + \frac{10}{7}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{3 x}{28} = \frac{10}{7}$$
Divide both parts of the equation by 3/28
x = 10/7 / (3/28)
We get the answer: x = 40/3
Sum and product of roots
[src]
sum
40/3
$$\frac{40}{3}$$
=
40/3
$$\frac{40}{3}$$
product
40/3
$$\frac{40}{3}$$
=
40/3
$$\frac{40}{3}$$
40/3
The graph