Mister Exam
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How to use it?
- Equation:
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Equation x^2-3x+5=0
-
Equation 2x-2=0
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Equation (x-4)²+(x+9)²=2x²
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Equation x^3-3*x+2=0
- Express {x} in terms of y where:
- 4*x-8*y=10
- -13*x+16*y=18
- 18*x+5*y=-18
- -2*x-10*y=17
- Derivative of:
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2x²
- Graphing y =:
- 2x²
- Integral of d{x}:
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2x²
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Identical expressions
- (x- four)²+(x+ nine)²=2x²
- (x minus 4)² plus (x plus 9)² equally 2x²
- (x minus four)² plus (x plus nine)² equally 2x²
- x-4²+x+9²=2x²
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Similar expressions
- log(2)(x²-1)=log(2)(2x-1)
- (x+4)²+(x+9)²=2x²
- (x-4)²-(x+9)²=2x²
- (x-4)²+(x-9)²=2x²
- (4x⁴)²-(x⁶-2x)+x⁶-(2x)²+1=5
(x-4)²+(x+9)²=2x² equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 2 2 (x - 4) + (x + 9) = 2*x
$$\left(x - 4\right)^{2} + \left(x + 9\right)^{2} = 2 x^{2}$$
Detail solution
Given the equation:
Expand expressions:
Reducing, you get:
Move free summands (without x)
from left part to right part, we given:
$$10 x = -97$$
Divide both parts of the equation by 10
We get the answer: x = -97/10
(x-4)^2+(x+9)^2 = 2*x^2
Expand expressions:
16 + x^2 - 8*x + (x + 9)^2 = 2*x^2
16 + x^2 - 8*x + 81 + x^2 + 18*x = 2*x^2
Reducing, you get:
97 + 10*x = 0
Move free summands (without x)
from left part to right part, we given:
$$10 x = -97$$
Divide both parts of the equation by 10
x = -97 / (10)
We get the answer: x = -97/10
Sum and product of roots
[src]
sum
-97 ---- 10
$$- \frac{97}{10}$$
=
-97 ---- 10
$$- \frac{97}{10}$$
product
-97 ---- 10
$$- \frac{97}{10}$$
=
-97 ---- 10
$$- \frac{97}{10}$$
-97/10
The graph