Move right part of the equation to left part with negative sign.
The equation is transformed from (x−16)+(x+81)=2x2 to −2x2+((x−16)+(x+81))=0 This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved using the discriminant. The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D = b^2 - 4*a*c - it is the discriminant. Because a=−2 b=2 c=65 , then
D = b^2 - 4 * a * c =
(2)^2 - 4 * (-2) * (65) = 524
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or x1=21−2131 x2=21+2131
Vieta's Theorem
rewrite the equation (x−16)+(x+81)=2x2 of ax2+bx+c=0 as reduced quadratic equation x2+abx+ac=0 x2−x−265=0 px+q+x2=0 where p=ab p=−1 q=ac q=−265 Vieta Formulas x1+x2=−p x1x2=q x1+x2=1 x1x2=−265