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How to use it?
- Equation:
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Equation 2(x+4)(x+2)=x^2+2x
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Equation 16-3x^2+14x=5x-14
- Equation log7(3-x)=2log7(4)
- Equation x1+x2+x3+x4+x5+x6+x7+x8=0
- Express {x} in terms of y where:
- (x^2+y^2-1)^3+x^2*y^3=0
- -1*x-19*y=-10
- 5*x+5*y=20
- 4*x-16*y=6
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Identical expressions
- x1+x2+x3+x4+x5+x6+x7+x8= zero
- x1 plus x2 plus x3 plus x4 plus x5 plus x6 plus x7 plus x8 equally 0
- x1 plus x2 plus x3 plus x4 plus x5 plus x6 plus x7 plus x8 equally zero
- x1+x2+x3+x4+x5+x6+x7+x8=O
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Similar expressions
- x1+x2+x3+x4+x5+x6+x7-x8=0
- x1+x2-x3+x4+x5+x6+x7+x8=0
- x1+x2+x3+x4-x5+x6+x7+x8=0
- x1+x2+x3+x4+x5+x6-x7+x8=0
- x1+x2+x3+x4+x5-x6+x7+x8=0
- x1-x2+x3+x4+x5+x6+x7+x8=0
- x1+x2+x3-x4+x5+x6+x7+x8=0
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What you mean?
- x^8 + x^7 + x^6 + x^5 + x^4 + x^3 + x^2 + x^1 = 0
You entered:
x1+x2+x3+x4+x5+x6+x7+x8=0
What you mean?
x1+x2+x3+x4+x5+x6+x7+x8=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 0
$$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} + x_{6} + x_{7} + x_{8} = 0$$
The graph
Rapid solution
[src]
x81 = -x1 - x2 - x3 - x4 - x5 - x6 - x7
$$x_{81} = - x_{1} - x_{2} - x_{3} - x_{4} - x_{5} - x_{6} - x_{7}$$
Sum and product of roots
[src]
sum
0 + -x1 - x2 - x3 - x4 - x5 - x6 - x7
$$\left(- x_{1} - x_{2} - x_{3} - x_{4} - x_{5} - x_{6} - x_{7}\right) + 0$$
=
-x1 - x2 - x3 - x4 - x5 - x6 - x7
$$- x_{1} - x_{2} - x_{3} - x_{4} - x_{5} - x_{6} - x_{7}$$
product
1*(-x1 - x2 - x3 - x4 - x5 - x6 - x7)
$$1 \left(- x_{1} - x_{2} - x_{3} - x_{4} - x_{5} - x_{6} - x_{7}\right)$$
=
-x1 - x2 - x3 - x4 - x5 - x6 - x7
$$- x_{1} - x_{2} - x_{3} - x_{4} - x_{5} - x_{6} - x_{7}$$
-x1 - x2 - x3 - x4 - x5 - x6 - x7