Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 1/(x-3)^2-3/(x-3)-4=0
-
Equation x^4+2*x^2-8=0
-
Equation (x-2)^5+(4-x)^5=2
-
Equation 6/(x+5)=-5
- Express {x} in terms of y where:
- 17*x-20*y=6
- 5*x-13*y=17
- 6*x+17*y=3
- 1*x+4*y=20
- Derivative of:
-
-5
- -5
- Integral of d{x}:
-
-5
-
Identical expressions
- six /(x+ five)=- five
- 6 divide by (x plus 5) equally minus 5
- six divide by (x plus five) equally minus five
- 6/x+5=-5
- 6 divide by (x+5)=-5
-
Similar expressions
- (126/x)+5=(126/(x-5))
- 0,6/x+5+=0,24/x-1
- 6*(x+4)-(5x+2)=-1
- 6/(x+5)=+5
- 6/(x-5)=-5
6/(x+5)=-5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{6}{x + 5} = -5$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$\frac{\left(-1\right) 6}{5} = x + 5$$
$$- \frac{6}{5} = x + 5$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + \frac{31}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = \frac{31}{5}$$
Divide both parts of the equation by -1
We get the answer: x = -31/5
$$\frac{6}{x + 5} = -5$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 6
b1 = 5 + x
a2 = 1
b2 = -1/5
so we get the equation
$$\frac{\left(-1\right) 6}{5} = x + 5$$
$$- \frac{6}{5} = x + 5$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + \frac{31}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = \frac{31}{5}$$
Divide both parts of the equation by -1
x = 31/5 / (-1)
We get the answer: x = -31/5
Sum and product of roots
[src]
sum
-31/5
$$- \frac{31}{5}$$
=
-31/5
$$- \frac{31}{5}$$
product
-31/5
$$- \frac{31}{5}$$
=
-31/5
$$- \frac{31}{5}$$
-31/5
The graph