Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation x-y=7
-
Equation 1/(x-1)^2+2/(x-1)-3=0
-
Equation 1/(x+6)=2
-
Equation (x-4)^2-x^2=0
- Express {x} in terms of y where:
- 7*x-1*y=-7
- 10*x-15*y=16
- -14*x-12*y=5
- 13*x-12*y=19
- Limit of the function:
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-5
- -5
- Derivative of:
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-5
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Identical expressions
- six /(x+ five)=- five
- 6 divide by (x plus 5) equally minus 5
- six divide by (x plus five) equally minus five
- 6/x+5=-5
- 6 divide by (x+5)=-5
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Similar expressions
- 0,6/x+5+=0,24/x-1
- 6/(x+5)=+5
- 6/(x-5)=-5
- (126/x)+5=(126/(x-5))
6/(x+5)=-5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$\frac{6}{x + 5} = -5$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
so we get the equation
$$\frac{\left(-1\right) 6}{5} = x + 5$$
$$- \frac{6}{5} = x + 5$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + \frac{31}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = \frac{31}{5}$$
Divide both parts of the equation by -1
We get the answer: x = -31/5
$$\frac{6}{x + 5} = -5$$
Use proportions rule:
From a1/b1 = a2/b2 should a1*b2 = a2*b1,
In this case
a1 = 6
b1 = 5 + x
a2 = 1
b2 = -1/5
so we get the equation
$$\frac{\left(-1\right) 6}{5} = x + 5$$
$$- \frac{6}{5} = x + 5$$
Move free summands (without x)
from left part to right part, we given:
$$0 = x + \frac{31}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = \frac{31}{5}$$
Divide both parts of the equation by -1
x = 31/5 / (-1)
We get the answer: x = -31/5
Sum and product of roots
[src]
sum
-31/5
$$- \frac{31}{5}$$
=
-31/5
$$- \frac{31}{5}$$
product
-31/5
$$- \frac{31}{5}$$
=
-31/5
$$- \frac{31}{5}$$
-31/5
The graph