2^x=10 equation
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The solution
Detail solution
Given the equation:
$$2^{x} = 10$$
or
$$2^{x} - 10 = 0$$
or
$$2^{x} = 10$$
or
$$2^{x} = 10$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 10 = 0$$
or
$$v - 10 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 10$$
We get the answer: v = 10
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(10 \right)}}{\log{\left(2 \right)}} = 1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
Sum and product of roots
[src]
$$1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
$$1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
$$1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
$$\frac{\log{\left(10 \right)}}{\log{\left(2 \right)}}$$
log(5)
x1 = 1 + ------
log(2)
$$x_{1} = 1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$