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2^x=10

2^x=10 equation

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Numerical solution:

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The solution

You have entered [src]
 x     
2  = 10
$$2^{x} = 10$$
Detail solution
Given the equation:
$$2^{x} = 10$$
or
$$2^{x} - 10 = 0$$
or
$$2^{x} = 10$$
or
$$2^{x} = 10$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 10 = 0$$
or
$$v - 10 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 10$$
We get the answer: v = 10
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(10 \right)}}{\log{\left(2 \right)}} = 1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
The graph
Sum and product of roots [src]
sum
    log(5)
1 + ------
    log(2)
$$1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
=
    log(5)
1 + ------
    log(2)
$$1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
product
    log(5)
1 + ------
    log(2)
$$1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
=
log(10)
-------
 log(2)
$$\frac{\log{\left(10 \right)}}{\log{\left(2 \right)}}$$
log(10)/log(2)
Rapid solution [src]
         log(5)
x1 = 1 + ------
         log(2)
$$x_{1} = 1 + \frac{\log{\left(5 \right)}}{\log{\left(2 \right)}}$$
x1 = 1 + log(5)/log(2)
Numerical answer [src]
x1 = 3.32192809488736
x1 = 3.32192809488736
The graph
2^x=10 equation