Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation (y^4+4*y^2-12)/4=0
-
Equation cos(x)=5
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Equation 2^x=16
-
Equation (x+5)^3=25*(x+5)
- Express {x} in terms of y where:
- -2*x-15*y=-1
- 10*x-2*y=11
- 4*x+18*y=-7
- 7*x+6*y=20
- Derivative of:
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2^x
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16
- Integral of d{x}:
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2^x
-
16
- Graphing y =:
- 2^x
- Sum of series:
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16
-
Identical expressions
- two ^x= sixteen
- 2 to the power of x equally 16
- two to the power of x equally sixteen
- 2x=16
-
Similar expressions
- 8/4^x-6*2^x+1=0
2^x=16 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$2^{x} = 16$$
or
$$2^{x} - 16 = 0$$
or
$$2^{x} = 16$$
or
$$2^{x} = 16$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 16 = 0$$
or
$$v - 16 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 16$$
We get the answer: v = 16
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(16 \right)}}{\log{\left(2 \right)}} = 4$$
$$2^{x} = 16$$
or
$$2^{x} - 16 = 0$$
or
$$2^{x} = 16$$
or
$$2^{x} = 16$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 16 = 0$$
or
$$v - 16 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 16$$
We get the answer: v = 16
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(16 \right)}}{\log{\left(2 \right)}} = 4$$
The graph