2*((|x|)+3)/3=13*((|x|)-1)/5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$\frac{23}{5} - \frac{29 x}{15} = 0$$
after simplifying we get
$$\frac{23}{5} - \frac{29 x}{15} = 0$$
the solution in this interval:
$$x_{1} = \frac{69}{29}$$
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$\frac{23}{5} - \frac{29 \left(- x\right)}{15} = 0$$
after simplifying we get
$$\frac{29 x}{15} + \frac{23}{5} = 0$$
the solution in this interval:
$$x_{2} = - \frac{69}{29}$$
The final answer:
$$x_{1} = \frac{69}{29}$$
$$x_{2} = - \frac{69}{29}$$
Sum and product of roots
[src]
$$- \frac{69}{29} + \frac{69}{29}$$
$$0$$
$$- \frac{4761}{841}$$
$$- \frac{4761}{841}$$
$$x_{1} = - \frac{69}{29}$$
$$x_{2} = \frac{69}{29}$$