Given the equation 2log(16)log(2x−5)=2 log(16)2log(2x−5)=2 Let's divide both parts of the equation by the multiplier of log =2/log(16) log(2x−5)=log(16) This equation is of the form:
log(v)=p
By definition log
v=e^p
then 2x−5=e2log(16)12 simplify 2x−5=16 2x=21 x=221