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How to use it?
- Equation:
- Equation 2x^2-50=0
-
Equation sinx=0,13
- Equation x^2-14/x-10x/x^2-14=3
-
Equation 29+y*4=309
- Express {x} in terms of y where:
- 15*x-15*y=16
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- (x^2+y^2-1)^3+x^2*y^3=0
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Identical expressions
- x^ two - fourteen /x-10x/x^ two - fourteen = three
- x squared minus 14 divide by x minus 10x divide by x squared minus 14 equally 3
- x to the power of two minus fourteen divide by x minus 10x divide by x to the power of two minus fourteen equally three
- x2-14/x-10x/x2-14=3
- x²-14/x-10x/x²-14=3
- x to the power of 2-14/x-10x/x to the power of 2-14=3
- x^2-14 divide by x-10x divide by x^2-14=3
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Similar expressions
- x^2+14/x-10x/x^2-14=3
- x^2-14/x+10x/x^2-14=3
- x^2-14/x-10x/x^2+14=3
x^2-14/x-10x/x^2-14=3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
2 14 10*x
x - -- - ---- - 14 = 3
x 2
x
$$\left(- \frac{10 x}{x^{2}} + \left(x^{2} - \frac{14}{x}\right)\right) - 14 = 3$$
Sum and product of roots
[src]
sum
____ ____
3 \/ 41 3 \/ 41
-3 + - - ------ + - + ------
2 2 2 2
$$\left(-3 + \left(\frac{3}{2} - \frac{\sqrt{41}}{2}\right)\right) + \left(\frac{3}{2} + \frac{\sqrt{41}}{2}\right)$$
=
0
$$0$$
product
/ ____\ / ____\ |3 \/ 41 | |3 \/ 41 | -3*|- - ------|*|- + ------| \2 2 / \2 2 /
$$- 3 \left(\frac{3}{2} - \frac{\sqrt{41}}{2}\right) \left(\frac{3}{2} + \frac{\sqrt{41}}{2}\right)$$
=
24
$$24$$
24
Rapid solution
[src]
x1 = -3
$$x_{1} = -3$$
____
3 \/ 41
x2 = - - ------
2 2
$$x_{2} = \frac{3}{2} - \frac{\sqrt{41}}{2}$$
____
3 \/ 41
x3 = - + ------
2 2
$$x_{3} = \frac{3}{2} + \frac{\sqrt{41}}{2}$$
x3 = 3/2 + sqrt(41)/2