Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^2-5*x+24=0
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Equation 12+3(x-1)=0
- Equation x^4-17*x^2+16=0
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Equation (x+6)^2=(15-x)^2
- Express {x} in terms of y where:
- -13*x+13*y=-20
- 15*x+6*y=16
- -20*x-13*y=9
- 14*x+1*y=-16
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Identical expressions
- twelve + three (x- one)= zero
- 12 plus 3(x minus 1) equally 0
- twelve plus three (x minus one) equally zero
- 12+3x-1=0
- 12+3(x-1)=O
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Similar expressions
- 12-3(x-1)=0
- (x^2-3*x+1)^2+3*(x-1)(x^2-3*x+1)=4*(x-1)^2
- 12+3(x+1)=0
12+3(x-1)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$3 x = -9$$
Divide both parts of the equation by 3
We get the answer: x = -3
12+3*(x-1) = 0
Expand brackets in the left part
12+3*x-3*1 = 0
Looking for similar summands in the left part:
9 + 3*x = 0
Move free summands (without x)
from left part to right part, we given:
$$3 x = -9$$
Divide both parts of the equation by 3
x = -9 / (3)
We get the answer: x = -3
The graph